main() { char *p; printf("%d %d ",sizeof(*p),sizeof(p)); } - Ans :1,2 because the *p is the pointer varible but the type is character.p is apointer variable.

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Question: main()
{
char *p;
printf("%d %d ",sizeof(*p),sizeof(p));
}

Answer: Ans :1,2 because the *p is the pointer varible but the type is character.p is apointer variable.

Category	C Interview Questions & Answers - Exam Mode / Learning Mode
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Question: main()
{
char *p;
printf("%d %d ",sizeof(*p),sizeof(p));
}

Answer:

Ans :1,2 because the *p is the pointer varible but the type is character.p is apointer variable.

Source: CoolInterview.com

1,4 its 1 because it holds d data of type character so only...
its 4 because its d address not any type... Source: CoolInterview.com

Answered by: Vivek Gopinathlal | Date: |

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correct answer is 1 and 2 because *p is a character pointer which holds the value of a character variable i.e. is 1 byte whereas sizeof(p) ...here p is used to hold the address of the character pointer hence 2(adress in integer) Source: CoolInterview.com

Answered by: Debapriya Maity | Date: |

Contact Debapriya Maity

1,2bcoz,
*p=means the value at address p(which hold the character i.e one byte in size)
sizeof(p)= indicates that the "p" is a pointer to char type data type which holds its address, i.e any how the pointer size is always 2byte , as the address is whole no . and 2 byte is sufficient for it Source: CoolInterview.com

Answered by: PRASANNA KUMAR DAS | Date: 3/12/2010 |

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