A scope resolution operator (::), can be used to define the member functions of a class outside the
class.

when we want to define the member function of the same class but the definition is at outside the class...at that time we have to use scope resolution operator...

you also use that operator to call a static member function by class name

class A
{
static void test()
{
cout<<"wellcome";
};
main()
{
A::test();
}
}

1.scope resolution operator is used to define the member function outside the class.
2.it is also used to print the value of global variable and local variable .
for example
int a=10;
void main()
{
int a=20;
cout<<a;
cout<<::a;
}
output
10 20

*Scope Resolution Operator(::) is a new operator in C++
*It is used to local variables or called on the outside in a class

Scope resolution operator tells the identifier (function or variable) belongs to perticular namespace or class.

scope is nothing but the visibility of a variable or a member. The members declared in the class by default wil have the class scope. It gives us the information like to which particular class a member belongs to.

.scope resolution is represented as "::"
.it is use for globel representation
.we use it for declaring a member function out of class
syntax:-
void get::data();
wear
void->returntype
get->classname
::->scope resolution
data->funtion name
par->agruments

scope resolution is a operator.it is used for classifying the function which is a part of that class.

Scope resolution operator is used to access the global variable in a block where one of the local variable in that block have the same name as global variable.

int Num;
class A
{
public:
void Func()
{
int A =10;
::A =20;//Definition of Global Variable
}
};

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