Array name is a constant pointer pointing to the base address(address of the first byte where the array begin) of the memory allocated. When you use arr[i], the compiler manipulates it as *(arr + i). Since arr is the address of the first element, the value of i must be 0 for accessing it. Hence all arrays begin with an index of 0.
The compiler thinks that 0 is a positive number. we have an integer range of -128 to 127. here -128 to -1 are negative numbers and 0 to 127 are positive numbers so array starts with the 0 as index.
What will be output of the following code #include using namespace std; class abc { public : void main() { cout<<" Its main function "< } }; int main(int c, char **v) { abc a; if(c<1) { cout<<" Error can not accept it "< exit(1); } cout<<" its in main program "< a.main();
How is static variable stored in the memory? ( if there are 2 functions in a file,and the static variable name is same (ex var) in both the function. how is it keep seperately in the memory).
Hey anybody help me to write code for this program wap which display year,month & day presents in a year for eg. 1. no. is 14 print 2 weeks 2. no is 90 print 3 months 3. no is 365 print 1 year user can input any no
DETAILS
Question :
Rating
(3.0) By 2 users
Added on
Views
Rate it! 
Posted by: kishore reddy 
Email Id :*
Answer :*
Enter the above shown code:*
