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Question: What is function overriding?

Answer: The function overloading is the technique in which you can make the function with more than one name but only if you will change the paramaters or the number of the paramaters.

Category Operator Overloading in C++ Interview Questions & Answers - Exam Mode / Learning Mode
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Question: What is function overriding?


The function overloading is the technique in which you can make the function with more than one name but only if you will change the paramaters or the number of the paramaters. Source:

function overriding is one in which functions have the same name and same number,type of arguments.. its only the implementations that differs.. they are accessed based on the object of the class being called Source:

Answered by: dharani | Date: | Contact dharani Contact dharani

function overloading is function name is same and parameter same but deffination of the function is deffrent .fuction perform the action is deffrent -deffrent <br>example-<br>class abc<br>{<br>int sum;<br><br>public int sum(int i, int j)<br>{<br>sum=i+j;<br>return(sum);<br>}<br>int mul;<br>public int sum(int i, int j)<br>{<br>mul=i*j;<br>return(mul);<br>}}<br>{<br> Source:

Answered by: ashish awasthi | Date: 9/24/2009 | Contact ashish awasthi Contact ashish awasthi

In OOAD we can give an idea of one interface and multiple defination Source:

Answered by: srividya | Date: 11/5/2009 | Contact srividya Contact srividya

it is a concept in which multiple function acess same data & information but different argument Source:

Answered by: rishi | Date: 12/17/2009 | Contact rishi Contact rishi

class abc<br>{<br>int sum;<br><br>public int sum(int i, int j)<br>{<br>sum=i+j;<br>return(sum);<br>}<br>int mul;<br>public float sum(int i, int j)<br>{<br>mul=i*j;<br>return(mul);<br>}}<br>{<br><br><br> Source:

Answered by: Shyam Parmar | Date: 1/19/2010 | Contact Shyam Parmar Contact Shyam Parmar

Function over loading means two functions will have same name but they differ in the number or type of arguments. <br><br>Whereas function overriding means two functions will have same name , type and number of arguments. Typically these two functions will be in different classes (base and derived for example). Source:

Answered by: Saravanan | Date: 1/19/2010 | Contact Saravanan Contact Saravanan

Function Overloading is defining more than one class with same function name but with diiferent number of arguments are with different datatypes of arguments<br><br><br>Example:<br>class sample<br>{<br>int s,m,d;<br>int sum(int a,int b)<br>{<br>s=a+b;<br>return(s);<br>}<br>int sum(int a,int b, int c)<br>{<br>m=a*b;<br>return(m);<br>}<br>float sum(float a,float b)<br>{<br>d=a/b;<br>returb(d);<br>}<br>} Source:

Answered by: Tamilarasan | Date: 3/3/2010 | Contact Tamilarasan Contact Tamilarasan

Function overloading is the feature of C++ where two functions can have same but different arguments for example <br><br>Class CFunctionOverload {<br><br>Public:<br>void OverloadFunction(void);<br>void OverloadFunction(int param1);<br>void OverloadFunction(int param1, int param2);<br>void OverloadFunction(float param1);<br>}<br><br> Source:

Answered by: Harish G | Date: 3/16/2010 | Contact Harish G Contact Harish G

Function Overriding:-<br> The functions having the same name,parameters but having different definitions is called function overriding. It basically deals with the concept of Inheritance.when a Base class having some function and the derived class of it having same function, then this creates a problem called function overriding. Source:

Answered by: Priyanshu Thukral | Date: 4/30/2010 | Contact Priyanshu Thukral Contact Priyanshu Thukral

function overloading is a technic in the function has same name with different parameter. Source:

Answered by: rushikesh kulkarni | Date: 7/10/2010 | Contact rushikesh kulkarni Contact rushikesh kulkarni

a function with same name can exist in 2 or more base class. now which function is used by derived class when it inherits the 2 classes is solved by overriding the function in derived class using (::) operator. Source:

Answered by: vaibhav panwar | Date: 7/19/2010 | Contact vaibhav panwar Contact vaibhav panwar

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