write this program and save it as pro.c....run....it will show the program to the consol and write the source code into data.txt file...................

#include<stdio.h>
void main()
{
FILE *fp,*ft;
char buff[100];
fp=fopen("pro.c","r");
if(fp==NULL)
{
printf("ERROR");
}
ft=fopen("data.txt","w+");
if(ft==NULL)
{
printf("ERROR");
}
while(getc(fp)!=EOF)
{

fscanf(fp,"%s",buff);
printf("%s ",buff);
fprintf(ft,"%s ",buff);
}
}

This seems to be taking longer than usual.

#include <iostream>
#include <fstream>
#include <string>
using namespace std;

int main () {
string line;

fstream myfile;
myfile.open("test.cpp",ios::in);
/* or use this:
ifstream myfile;
myfile.open("test.cpp");
*/

if(myfile.is_open()){
while(! myfile.eof()){
getline(myfile,line);
cout << line <<endl;
}
myfile.close();
}else{
cout<<"unable to open the file";
}
return 0;
}

A compiled program cannot generate its sourece code. A compiled program does not know where its source lie.

#include "stdafx.h"
#include "stdio.h"
#include "stdlib.h"
#include "iostream"
using namespace std;

class abc
{
public :
int main()
{
cout<<" Its main function "<<endl;
return 0;
}
};

int main(int c, char **v)
{
abc a;
/******************That will print the output**********/
char buff[100];
strcpy(buff, "type ");
strcat(buff, __FILE__);
system(buff);
/******************************************/
printf(" Address of main Function = %u ",main);
if(c<1)
{ cout<<" Error can not accept it "; }
cout<<" its in main program "<<a.main()<<endl;

return 0;
}

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