No. There?s no way to tell, at runtime, how many elements are in an array parameter just by looking at the
array parameter itself. Remember, passing an array to a function is exactly the same as passing a pointer to
the first element.

In VC++, this is wat i tried

main()
{
int a[10];
printf("%d", sizeof(a);
}

Output: 40

This shows dat the sizeof can be operated on arrays as well.

20

yes

yes

GOD!!!! so many 'yes'...

The answer is NO.. Pass the array element to a function and see. The array is passed as a pointer (pointer to the begining address of the array)..

no,size of operator is compile time operator, it is used for determine the lenght of array and structure but in compile time not run time

sizeof() is an operator, it is not a function, this is reason you are getting the answer out at 40.

Try the following:

# include <stdio.h>
# include <malloc.h>

void printf_sz(int a[])
{
printf(" Sizeof : %d", sizeof(a));
}



main()
{
int a[20];

printf (" Sizeof : %d", sizeof(a));

printf_sz(a);


}

The output of the above program is 80 and 4.

Check for yourself

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