In which line of the following, an error would be reported? 1. #define CIRCUM(R) (3.14*R*R); 2. main() 3. { 4. float r=1.0,c; 5. c= CIRCUM(r); 6. printf("n%f",c); 7. if(CIRCUM(r))==6.28) 8. printf("nGobbledygook"); 9. }

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Question :
In which line of the following, an error would be reported?
1. #define CIRCUM(R) (3.14*R*R);
2. main()
3. {
4. float r=1.0,c;
5. c= CIRCUM(r);
6. printf("n%f",c);
7. if(CIRCUM(r))==6.28)
8. printf("nGobbledygook");
9. }

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Answers:

The correct answer is B(Line 5). #define CIRCUM(R) (3.14*R*R);means wherever the program encounters CIRCUM(R) replace it with (3.14*R*R); including the semicolon. So the line number 5 will have 2 semicolons continuosly.Got it...

Hi, the above answer does not work on my compiler.

I am working on DEV C++.

Here error occurs on "LINE 7" but not on "LINE 5". Though there are many ; (semicolon),it will be considered as a null statement in "LINE 5" where as it will give error in "LINE 7".

if( (3.14*R*R); ) == 6.28) this gives the error.

Modified code is :

#define CIRCUM(R) (3.14*R*R);
main()
{
float r=1.0,c;
c= CIRCUM(r);; //becomes c=(3.14*R*R);;;
printf("n%f",c);
if(CIRCUM(r)==6.28) //Here is the error
printf("nGobbledygook");
getch();
}

Posted by: Syed Baseer Ahmed

  Contact Syed Baseer Ahmed

Correct code would be

#include <stdio.h>
#define CIRCUM(R) (3.14*R*R)

main()
{
float r=1.0,c;
c= CIRCUM(r);
printf("n%f",c);
if(CIRCUM(r)==6.28)
printf("nGobbledygook");
}

Posted by: Unknown

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