What will be the output of the following program in UNIX OS with CC compiler and TC compiler? int main() { int i=5; printf(" %d",++i + ++i + ++i + ++i + ++i ); } If any difference then Why it is difference?

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Question :
What will be the output of the following program in UNIX OS with CC compiler and TC compiler?

int main()
{
int i=5;
printf(" %d",++i + ++i + ++i + ++i + ++i );
}
If any difference then Why it is difference?

Category C Interview Questions

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Added on 7/18/2006

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Answers:

Output: 41.

For different compiler ther will be same output.

Expression will be evaluated in following manner.
(((++i + ++i) + ++i) + ++i) + ++i
6
7
7 + 7 = 14
8
14 + 8 = 22
9
22 + 9 = 31
10
31 + 10 = 41.

1.on tc 40
2.on unix cc 41
1. on tc evaluation is from right to left and ++i ++ i + ++i is treated as simple as it is

2. But on unix

++i ++ i + ++i is treated as (++i + ++i) + ++i
Means parenthesis are placed during evaluation
You can try for
i=5
printf(" %d", ++i + ++i)

on unix cc 14

on tc 13

Posted by: rajeev kumar

  Contact rajeev kumar

Output:40

Posted by: varun kumar Gupta

  Contact varun kumar Gupta

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