#include<conio.h>
#include<stdio.h>
#include<string.h>
void main()
{
//abcd are occurs two times in an array f[30]
char f[30]={"abcdabcd"},name[30];
int i,j,m,n;
clrscr();
m=strlen(f);
n=m;
for(i=0;i<n;i++)
for(j=i+1;j<m;j++)
if(f[i]==f[j])
{
f[j]='$';
}
j=0;
printf("name=%s",f);
for(i=0;i<m;i++)
{
if(f[i]!='$')
{
name[j]=f[i];
j++;
}
}name[j]='

int main()
{
//2 and 3 are repeating
int a[10] = {1,2,3,2,4,5,6,3,2,3};
int i,j;
for(i=0;i<9;i++)
{
for(j=i+1;j<10;j++)
{
if(a[i] == a[j])
a[j] = 0;//Make the duplicate as 0;
}
}

If you have the better answer, then send it to us. We will display your answer after the approval.

Name :*
Email Id :*
Answer :*
Verification Code	Not readable? Load New Code
Enter the above shown code:*
	Inform me about updated answers to this question