In programing instruction, suppose, y=1 if z=y than value of z is 1 (because first it assign value of y to z and than increment in y by 1) and if z= y than value of z is 2 (because it increment in y by 1 and than assign that value to z) so that, in our case,
z = y y y y
Z = 1 3 4 4 at finally,
Z = 12.

z=y++ + ++y + ++y + y++
= 1 + 3 + 4 + 4
=12.
How the above values are calculated is explained below:
The above expression hold y in 4 places.
In first,it hold 1 and the value 1 is used in expression then incremented because it is postfix y++.
Now y=2.
In second term,y is incremented before it is used because it is ++y.so here y=2+1=3.
In third term, y is also incremented before it is used because it is y++.so here y=3+1=4.
In fourth term,y is used then only it is incremented because it is y++.so the value 4 is used here.
After that the present y hold the value 4+1=5.

12

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